Words That Mean Perfect

Introduction to Words That Mean Perfect:

Words that mean perfect in math is the operation in the expression done perfect with correct procedure. Each expression has different operation and different procedure. To get the result from or to solve the expression as by the corresponding procedure, we say as the words perfect. In this article, we see about the words that mean perfect.

Is this topic Simplify the Expression hard for you? Watch out for my coming posts.

Example Problem – Words that Mean Perfect:


Example 1:

What is the words that mean perfect of the expression as (x + 1)?

Solution:

Given: (x + 1)

To find:  Words that mean perfect for the expression is the result of the given expression.

(x + 1) = (1 + 1) + (2 + 1) + (3 + 1) + (4 + 1)

= 2 + 3 + 4 + 5

= 14

Thus the words that mean perfect for the expression is the result of the expression is 14

Answer: Perfect 14

Example 2:

Which of the following is the words that mean perfect form the expression 33?

Option:

a)     9

b)    27

c)     9

d)    3

Solution:

Given: Expression is 3^3

The given expression is the 3 to the power of 3. Thus the number 3 is multiply itself as three times.

Step 1: 3^3 = 3 * 3 * 3 = 27

Thus 27 is the words that mean perfect to the expression as 33. Here the perfect words that given in option as b which is said to be as correct.

Answer: Option b - - - > 27

I have recently faced lot of problem while learning What is a Perfect Square, But thank to online resources of math which helped me to learn myself easily on net.

Example Problem – Words that Mean Perfect:


Example 3:

Which of the following expression is correct for the words that mean perfect of the number 25?

Option:

a)     5 + 5

b)    20 * 5

c)     25 – 5

d)    5 * 5

Solution:

Step 1: To find the correct expression for the perfect number 25.

Step 2: Check each option which given the words that mean perfect as 25.

Option a: 5 + 5, the sum of 5 and 5 is 10

Option b: 20 * 5, the product of 20 and 5 is 100

Option c: 25 – 5, the result of 5 is subtracted from 25 is 20

Option d: 5 * 5. the product of 5 and 5 is 25

Thus the expression given in option d gives the words that mean perfect of 25.

Answer: Option d - - - > 25

Solve Perfect Triangles

Introduction to solve perfect triangles:

Triangles are three sided polygons. They are classified into equilateral triangles, isosceles, and right angled triangles. To solve perfect triangles, they should contain equal sides and angles. Perfect triangles include equilateral and right angled triangles. In triangles, we find the area, perimeter and the angles. Now we see some problems to solve perfect triangles.


Some basic properties of triangles and problems


Area formula = `1/2(b xx h)`

Perimeter formula = (a + b + c)

Interior angle = (n – 1) 180° and

Exterior angle = 360°/n

Where,

n – Number of sides

Problems to solve perfect triangles:

Example 1:

What is the area of an equilateral triangle, if it one of the side measures 5 cm?

Solution:

We know that, the equilateral triangle has same length in all the sides.

Formula to find the area of the triangle is given by,

Area =`1/2(b xx h)`

Here it has same breadth and length.

On substituting the side value, that is 5 in the areas formula,

Area =`1/2(5 xx 5)`

= `1/2(25)`

=12.5

Thus the area of the given equilateral triangle is 12.5 cm2.

Example 2:

Find the perimeter of the right angled triangle the sides are given as 3 cm, 6 cm, and 9 cm.

Solution:

We know the formula to find the perimeter of the given triangle

Perimeter = (a + b + c)

= (3 + 6 + 9)

= 18

Therefore the perimeter of the triangle is 18 cm.

Having problem with Sum of Exterior Angles Formula keep reading my upcoming posts, i will try to help you.

More problems to solve perfect triangles


Example 3:

Find the interior and exterior angles for the right angled triangle.

Solution:

Formula to find Interior angle = (n – 2) 180°

Here a right angled triangle has 3 sides. So n = 3

(n – 2) 180 = (3 – 2)180

= 180

The interior angle for a right angled triangle is 180°

Now to find the exterior angle, we know the formula as

`360/n = 360/3`

= 120

Hence the exterior angle is 120°.

Example 4:

A triangle has a total perimeter of 34 cm. If two sides are given as 12 cm and 14 cm, what is the length of the third side?

Solution:

Perimeter of the triangle is (a + b + c)

We know the two side’s length as 12 and 14.

So a = 12 cm and b = 14 cm

Let the third side be c.

12 + 14 + c = 34

26 + c = 34

Subtract by 26 on both sides, we get

26 – 26 + c = 34 – 26

c = 8

Therefore the third side’s length is 8 cm.

These are some example problems to solve perfect triangles.

Definition of Perfect Square

Introduction to definition of perfect square:

The definition of perfect square is defined as the important topics in mathematics. Product of two integer gives another integer is known as the perfect square. The rational number with the square root is known as the perfect square.  For example, 16 is known as the perfect square integer, since it has 4  `xx`  4 is the two product for 16. This article shows the definition of perfect square with brief explanation and some example problems.


Explanation to definition of perfect square


The explanation given for the perfect square definition is as follows,

Trinomial and binomial functions are also written as the perfect square.
Trinomial Perfect square = x2 + 6x + 9
Trinomial Perfect square  = (x + 3)2 .
Perfect square Example:

0 , 1 , 4, 9, 16, 25, etc.

`16/36` , `16/25` are also the examples of perfect squares.


Example problems to definition of perfect square


Problem 1: Which of the following integer when added to 12 to make perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Solution:

Step 1: Given:

Number = 12

Step 2: To find:

Perfect square

Step 3: Solve:

12 + 4 = 16

16 = 42

16 = 4 `xx` 4

Therefore 4 is the integer when added to 12 to give perfect square.

Answer: Option d

Problem 2: Which of the following integer when added to 24 to make perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Solution:

Step 1: Given:

Number = 24

Step 2: To find:

Perfect square

Step 3: Solve:

24 + 1 = 25

25 = 52

16 = 5 `xx` 5

Therefore 1 is the integer when added to 24 to give perfect square.

Answer: Option c

Understanding math online tutor is always challenging for me but thanks to all math help websites to help me out.

Practice problems to definition of perfect square


Problem 1: Which of the following integer when added to 25 to make perfect square.

Options:

a) 2

b) 1

c) 3

d) 4

Answer: Option b

Problem 2: Which of the following integer when added to 33 to make perfect square.

Options:

a) 2

b) 1

c) 3

d) 4

Answer: Option c

Perfect Square Definition

Introduction to perfect square definition:
Perfect square is defined as one of the most important topics in mathematics. Perfect square is defined as the product of integer gives the integer. Also, the perfect square is defined as the rational number with the square root. For example, 9 is called as the perfect square, since it has 3  `xx`  3 is the product terms. In this article, we are going to study about the perfect square definition in detail.

Please express your views of this topic Factor Trinomial by commenting on blog.

Explanation to perfect square definition


The explanation given for the efinition of perfect square is as follows,

Perfect square can also written using the trinomial and binomials.
Perfect square trinomial = x^2 + 4x + 4
Perfect square binomial = (x + 2)^2 .
Example of perfect square:

0 , 1 , 4, 9, 16, 25, etc.

`9/16` , `16/25` are also known as the perfect squares.


Example problems to perfect square definition


Problem 1: Find the integer which the number 17 as the perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Solution:

Step 1: Given:

Number = 17

Step 2: To find:

Perfect square

Step 3: Solve:

17 - 1 = 16

16 = 42

16 = 4 `xx` 4

Therefore 1 is the number which makes 17 as the perfect square.

Answer: Option c

Problem 2: Find the integer which the number 27 as the perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Solution:

Step 1: Given:

Number = 27

Step 2: To find:

Perfect square

Step 3: Solve:

27 - 2 = 25

25 = 52

125 = 5 `xx` 5

Therefore 2 is the number which makes 27 as the perfect square.

Answer: Option a

Is this topic cbse books for class 9 hard for you? Watch out for my coming posts.

Practice problems to perfect square definition


Problem 1: Find the integer which the number 19 as the perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Answer: Option b

Problem 2: Find the integer which the number 29 as the perfect square.

Options:

a) 2

b) 3

c) 1

d) 4

Answer: Option d

Perfect Square Formula

Introduction to the perfect square formula :
In the mathematics, the perfect square is sometimes known as a square number. The perfect square is the integer square or also represented as the perfect square is the product of some of the integer with itself. The perfect square numbers are only the positive numbers not having the negative numbers. The positive values are not having perfect square divisors except only one is known as square free.



Formula for perfect square formula :


The regular notation for the perfect square formula is the perfect square of the number n not the n x n that is not the product of the number n.The model of square can be used to number systems.

Explanation of the perfect square formula:

In the arithmetic we have the following perfect squares like,`1^2=1,2^2=4,3^2=9,..`

In this way we can able to make the perfect square in the algebra. It is explained in the following ways, take the expansion of `(a+b)^2`

`(a+b)^2=(a+b)(a+b)=a(a+b)+b(a+b)=a^2 +ab+ba+b^2=a^2+b^2+2ab`

`a^2+b^2+2ab` it is the perfect square formula of the (a+b).

the expansion of `(a-b)^2`

`(a-b)^2=(a-b)(a-b)=a(a-b)-b(a-b)=a^2-ab-ba+b^2=a^2+b^2-2ab`

`a^2+b^2-2ab` it is the perfect square formula of the ( a-b).

Geometrical representation:

Consider the square of a side (a + b) units .

Area of the square `=(side)^2=(a+b)^2`

Area of the square is same as the areas of the four rectangles.so it can be written as,

Area of the square `= a^2+ab+ab+b^2=a^2+2ab+b^2.`

Understanding Area of Square Formula is always challenging for me but thanks to all math help websites to help me out.

Example 1 for the perfect square formula:


To solve the following `(x+5)^2`

Solution:

Given,

`(x+5)^2 =(x+5)(x+5)=x(x+5)+5(x+5)=x^2+5x+5x+25=x^2+10x+25.`

The result of the equation is `x^2+10x+25.`

Example 2 for the perfect square formula:

To solve the following `(a+2)^2`

Solution:

Given,

`(a+2)^2 =(a+2)(a+2)=a(a+2)+2(a+2)=a^2+2a+2a+4=a^2+4a+4.`

The result of the equation is` a^2+4a+4.`

Example 3 for the perfect square formula:

To solve the following `(a-2)^2`

Solution:

Given,

`(a-2)^2 =(a-2)(a-2)=a(a-2)-2(a-2)=a^2-2a-2a+4=a^2-4a+4.`

The result of the equation is` a^2-4a+4.`

Learn Basic Mathematics Tutoring

Introduction to learn basic mathematics tutoring

Mathematics is used throughout the world in many fields like, engineering, science, and medicine. Tutoring means receiving instruction or help from tutor. Through tutoring students can get more help. Tutors explain every concept in step by step so that student cans easily learning and understands the concept. In basic math the students can receive first level of math education. In this article we shall learn basic mathematics tutoring example problems. Is this topic 6th grade math test prep hard for you? Watch out for my coming posts.


Learn basic mathematics tutoring example problems


Example:

Express 3678 g in to kilograms

Solution:

1000 g = 1 kg

Hence `3678/1000`

= 3.678 kg

Note:

3678 g = 3000 g + 600 g + 70 g + 8 g

= 3 × 1000 g + 6 × 100 g + 7 × 10 g + 8 g

= 3 × 1 kg + 6 × 1 hg + 7 × 1 dag + 8 g

= 3 kg + 6 hg + 7 dag + 8 g

Example:

Solving the equation 6x – 45 = 2x + 3

Solution:

6x – 45 = 2x + 3

6x = 2x + 3 + 45

6x – 2x = 48

4x = 48

x = 48 x` 1/4`

Therefore x = 12

Example:

A book is bought `$` 120 and sells it profit at a rate of 10% find the selling price of the book.

Solution:

Profit    = 10 % of `$ ` 120

= `10/100` x 120 = 12

Selling price      = cost price + profit

= 120 + 12

The selling price is` $` 132

Example:

The area of the triangle is 1600m2. The triangle base field is 40 m. find the height of the triangle.

Solution:

Given Area of the triangle, A     = 1600m2

Base of the triangle = 40 m

Height of the triangle =?

Area of triangle formula = `1/2 ` b x h

`1/2` x (40) x h =1600

20 x h   = 1600

h          = `1600/20`

Therefore the height of the triangle field = 80 m

I have recently faced lot of problem while learning Algebra Math Problems, But thank to online resources of math which helped me to learn myself easily on net.

Learn basic mathematics tutoring practice problems


Problem:

Solving the equation 7x – 53 = 2x + 2

Answer:

x = 11

Problem:

The area of the triangle is 1400m2. The triangle base field is 40 m. find the height of the triangle.

Answer:

Height of the triangle field = 80 m

Problem:

A book is bought `$` 180 and sells it profit at a rate of 10% find the selling price of the book.

Answer:

The selling price is` $ ` 198

Prepare for Learn Mathematics

Introduction to prepare for learn mathematics:

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics is used throughout the world as an essential tool in many fields, including natural science, engineering, medicine, and the social sciences. In this article we shall prepare for learn mathematics problems. (Source: Wikipedia)


Prepare for learn mathematics with example problem


Here we are going to prepare for learn mathematics example problem with detailed solutions.

Example:

A marked of the land price is `$` 7500. The land owner decides to give 6% discount on the original price of the land. What is the selling price of the land?

Solution:

Marked price of the land             =          `$` 7500

Rate of discount                        =          6%

Actual discount amount =          7500x` 6/100`

=          `$` 450

=          7500 – 450

=          `$` 7050

Selling price of the land =          marked price of the land – discount price of the land

=          7500 – 450

=          7050

Therefore the selling price of land is `$` 7050.

Example:

Joes deposited at a bank `$` 9000. The bank paid simple interest on deposit amount and credited yearly at the 6% rate of interest per annum. Find the total money she gets at the end of 5th years.

Solution:

Formula for simple interest = `(PNR)/(100)`

Present amount P = `$` 9000

Rate of interest year r = 6%

Total number of year = 5

A = `(9000*5*6)/(100)`

Interest = 2700

Total amount = Deposit amount + Interest

= `$` 9000 + `$` 2700

= `$` 11700


Prepare for learn mathematics with practice problem


Problem:

A marked of the land price is `$` 2500. The land owner decides to give 7% discount on the original price of the land. What is the selling price of the land?

Answer:

The selling price of land is `$` 2325.

Problem:

Joes deposited at a bank` $` 8000. The bank paid simple interest on deposit amount and credited yearly at the 8% rate of interest per annum. Find the total money she gets at the end of 5th years.

Answer:

`$` 11200

Online Solve Mathematics

Introduction to online solve mathematics:

Mathematics is the study of the dimension, properties, and interaction of quantities and sets, using symbols and numbers. Mathematics is used in our daily life. Mathematics includes algebra, geometry, calculus, etc. Step by step explanation is very useful to understand the concepts of math. Through the online, student can gain more knowledge even by staying in their home itself. Now, we are going to see some of the problems to solve mathematics online.

Looking out for more help on How do you Simplify Expressions in algebra by visiting listed websites.

Problems to solve mathematics online:


Example problem 1:

Simplify the expression: 15x + 8y - 2 + 7x + 12y + 17

Solution:

This expression can be simplified by combining like terms

+15 x and +7x are like terms, and can be combined to give +22x,

+8y and +12y combine to give +20y, and

-2 and +17 combine to give +15.

So after simplifying, this expression becomes: 22x + 20y + 15.

Example problem 2:

Subtracting fractions: `3/4 - 1/5`

Solution:

The common denominator of 4 and 5 is 20.

In this example, we need to multiply the fraction  `3 / 4`  by 5 and multiply `1 / 5` by 4. So, Equivalent fraction of `3 / 4` is `15 / 20` and the equivalent fraction of `1 / 5` is` 4 / 20` .

`3 / 4 - 1 / 5 = 15 / 20 - 4 / 20`

Now, the denominators are same, so we have to subtract the numerators.

`3 / 4 - 1 / 5 = (15 - 4) / 20`

=`11 / 20`

So, the answer is `11 / 20.`


Few more problems to solve mathematics online:


Example problem 3:

Solve the inequality s: 17.5s – 33 < 37

Solution:

17.5s – 33 < 37

Add 33 on both side of the inequality

17.5s – 33 + 33 < 37 + 33

17.5s < 70

Divide by 17.5 on both side of the inequality

`(17.5s) / 17.5 < 70 / 17.5`

s < 4

So, the solution is (-infinity, 4).

Example problem 4:

The base of a cylinder has the radius of 4.5 cm and the height is 8 cm. Determine the lateral surface area of the solid cylinder.

Solution:

Radius = 4.5cm

Height = 8cm

Formula for lateral surface area = 2* `pi` * r * h.

Here given that, r = 4.5cm and h = 8cm.

Lateral surface area of the cylinder = 2 * 3.14 * 4.5 * 8

= 226.29 cm^2.

So, the lateral surface area of cylinder is 226.29 cm^2.


Practice problems to solve mathematics online:


1)    Subtracting fractions: `3 / 5 - 1 / 4` . (Answer: `7 / 20` ).

2)    Solve the inequality: 13.4s – 2.6 > 51. (Answer: s > 4).

3)    The base of a cylinder has the radius of 3.8 cm and the height is 7 cm. Determine the lateral surface area of the solid cylinder. (Answer: 167.05 cm^2).

Solving Learning Mathematics

Introduction to solving learning mathematics:

Mathematics is related to the properties, dimension, and interaction of quantities and sets, using numbers and symbols. Mathematics is used in our daily life. Mathematics includes various topics such as algebra, geometry, trigonometric, calculus, etc. Step by step clear explanation is more helpful to understand the basic concepts involved in math. Now, we are going to see some of mathematics problems learning.

Solving learning mathematics problems:


Example problem 1:

Solve for the variable r:  3r – 13 = 47 - 2r

Solution:

3r – 13 = 47 - 2r

Add 13 on both sides of the equation

3r – 13 + 13 = 47 - 2r + 13

3r = -2r + 60

Add 2r on both sides of the equation

3r+ 2r = -2r + 60 + 2r

5r = 60

Divide by 5 on both sides of the equation

`(5r) / 5 = 60 / 5`

By solving this, we get

r = 12

So, the answer is r = 12.

Example problem 2:

Marked price of a furniture is `$` 450. It is sold at a discount of 20%. Find the discount and its selling price.

Solution:

Marked price of the furniture = `$` 450

Rate of discount = 20%

Discount allowed = 20% of `$` 450=`20 / 100` × `$` 450 = `$` 90

Therefore, Selling price of the furniture = `$` 450 – `$` 90 = `$` 360.


Few more solving learning mathematics problems:


Example problem 3:

Find the Mean value for the given set of numbers: 42, 48, 43, 45.

Solution:

Mean = Sum of the values
Total number of values.

Mean   =`(42 + 48 + 43 + 45) / 4`

=`178 / 4`

= 44.5

So, the mean value is 44.5.

Example problem 4:

Find x and y intercept for the equation of line 13x +6.5y = 26.

Solution:-

Given equation is 13x + 6.5y = 26.

x intercept means plug y = 0 in the given equation

13x + 6.5(0) = 26

13x = 26

By Solving this, we get

x = 2

y intercept means plug x = 0 in the given equation

13(0) + 6.5y = 26

6.5y = 26

y =4

So, the x intercept is (2, 0) and the y intercept is (0, 4).

Understanding Piecewise Functions Practice is always challenging for me but thanks to all math help websites to help me out.

Practice problems for mathematics learning:
1) Find the value of p: 7p +17 = 66.

(Answer: p = 7).

2)  Find x intercept for the equation of line 4x + 6y = 30.

[Answer: (7.5, 0)].

3) Find the mean value for the given set of numbers: 10, 20, 30, 40.

(Answer: 25).

Solving Ks-3 Mathematics Tuitions

Introduction to solving ks-3 mathematics tuitions:

Mathematics is one of the basic knowledge to be known. Ks-3 means key stage 3 which refers to the three year schooling for students who are in the age of 11-14. These types of systems are followed in England and Northern Ireland. The ks-3 term of study is generally expressed as year 7, year 8 and year 9 studies. In online, many websites provides free help on ks-3 maths problem. In online, students can get help with all subject problems. In this article, we are going to see about, ks-3 mathematics problem solving online.


Practice problems on solving ks-3 mathematics tuitions:


Solving Ks-3 mathematics:


Ex 1: Find the place value of the number 9 in the given number 319
Sol :  The place value of 9 in the given number is, 1’s place
Hence the answer is 1’s place.
Ex 2:  Write the expanded form of 8290.
Sol :  The number 8290 can be written in expanded form as,
8290 = 8000 + 200 + 90
The answer is 8000 + 200 + 90.
Ex 3:  Express 16/32 as a percentage.
Sol :  16/32 = 16/32*100
On solving this we get,
= 0.5*100
= 50%
The solution is 50%
Ex 4:   In a school, there are total of 462 students. In that school there are 11 classrooms, find the number of students for each class.
Sol :  Total number of students = 462
Number of classrooms = 11
Number of students per class = x
Number of students per class = Total number of students/ number of classrooms
On solving this we get,
= 462/11
= 42
The answer is 42.

Ex 5:  Find the value of 5x, when x is 12
Sol :  Given: x = 12
5x = 5*12
= 60
Then answer is 60.
Ex 6:  Find the value of 4x2 + 3, when x is 4.
Sol :  Given: x = 4
4x2 + 3 = 4(4)2 + 3
= 4(16) + 3
= 64 + 3
= 67
The answer is 67.


Practice problems solving ks-3 mathematics tutions:


Problem 1: Find the place of 8 in the given number, 3859
Solution: 100’s place
Problem 2: Express 32/45 as a percentage
Solution: 71.11%
Problem 3: Find x, 22x, where x = 5
Solution: 110
Problem 4: Express 178 cents in dollars
Solution: 1.78 dollars

Prepare for Mathematics Problems

Introduction to prepare for mathematics problems:

Mathematics is the study of the dimension, properties, and interaction of quantities and sets, using symbols and numbers. Mathematics is used in our daily life. Mathematics includes algebra, geometry, calculus, etc. Step by step explanation is very useful to understand the concepts of math. Now, we are going to prepare for mathematics problems.

Is this topic One Sided Limit hard for you? Watch out for my coming posts.

Problems to prepare mathematics:


Example problem 1:

Solve an equation for the variable r:` (r / 4)` - 28 = -33

Solution:

`(r / 4) ` - 28 = -33

Add 28 on both sides of the equation

`(r / 4) ` – 28 + 28 = - 33 + 28

`(r / 4) ` = -5

Multiply 4 on both sides of the equation

`(r / 4)` * 4 = -5 * 4

r = -20

So, r = -20 is the solution of the given equation.

Example problem 2:

Solve the inequality: 2r – 83 < -61

Solution:

2r – 83 < -61

Add 83 on both side of the inequality

2t – 83 + 83 < -61 + 83

2r < 22

Divide by 2 on both side of the inequality

`(2r) / 2 < 22 / 2`

r < 11

So, the solution is (-infinity, 11).


Few more problems to prepare mathematics:


Example problem 3:

Find the x and y intercept of the equation: 7x + 3.5y = 14.

Solution:

7x + 3.5y = 14

To find the x intercept value, plug y = 0 in the given equation

7x + 3.5(0) = 14

7x = 14

x = 2

So, the x intercept is (2, 0).

To find the y intercept value, plug x = 0 in the given equation

7(0) + 3.5y = 14

3.5y = 14

y = 4

So, the y intercept is (0, 4).

Example problem 4:

Find the area of trapezoid whose parallel sides are 10cm and 7cm and height is 8cm.

Solution:

Base 1 = 10cm

Base 2 = 7cm

Height = 8cm

Area of trapezoid = `(1 / 2)` h(a + b)

= `(1/2)` (8) (10 + 7)

= 68cm^2.

So, the area of trapezoid is 68cm^2.

I have recently faced lot of problem while learning Profit and Loss, But thank to online resources of math which helped me to learn myself easily on net.

Practice problems to prepare mathematics:


1)      Solve for the variable d:  10d + 4 = 18 + 3d (Answer: d = 2).

2)      Solve for the variable r:  18r + 1 = 37 (Answer: r = 2).

3)      Find the area of trapezoid whose parallel sides are 9cm and 6cm and height is 5cm. (Answer: 37.5cm^2).