Showing posts with label Number Theory. Show all posts
Showing posts with label Number Theory. Show all posts

Tuesday, March 12

Solving Number Theory Problems

Introduction of solving number theory problems
Number theory is the theory about numbers which is called "the queen of mathematics" by the legendary mathematician Carl Friedrich Gauss, number theory is one of the oldest and largest branches of pure mathematics. The number theory delves deep into the structure and nature of numbers, and explores the remarkable, often beautiful relationships among them.

The number theory has many different types of numbers:

Solving Natural numbers problemssolving Prime numbers problems
solving Integers problems
solving Algebraic numbers problems
solving imaginary numbers problems
solving transcendental numbers problems


Example problems for solving number theory


Example: 1

Find the values of consecutive numbers where the sum of the two numbers is 161.

Solution:

Let as assume the two consecutive numbers be x, x+1.

Where the sum is 161 so,

x + x + 1 = 161

2x + 1 = 161

2x = 160

x = 80

Therefore, x + 1 = 80 + 1 = 81

So the consecutive numbers is 80 and 81.

I like to share this Number Sense with you all through my article.

Example: 2

Find all integers n such that n − 18 and n + 18 are both perfect Squares.

Solution:            Let as assume n −18 = a2 and n +18 = b2.

Then b2 −a2 = 36, so (b−a) (b+ a) = 22 .32.

Because b−a and b+a are of the same parity,

So, the following possibilities are:  b − a = 2, b + a = 18, yielding b = 10, a = 8,

And b − a = 6, b+a = 6, yielding a = 0, b = 6.

Hence the integers with this property are n = 46 and n = 18.


Example :3


Find the values of consecutive numbers where the product of the two numbers is 121.

Solution:-

Let as assume the two consecutive numbers be x, x +1.

Where the product is 121 so,

x * (x + 1) = 121

x^2 + x = 121

x^2 + x – 121 = 0

x^2 + 12x – 11x – 121 = 0

(x + 12) (x - 11) = 0

(x + 12) = 0 (or) (x - 11) = 0

x = -12 (or) x = 11

-12 is not possible to get 121

Therefore we take x = 11

So, x + 1 = 11 + 1 = 12

The consecutive numbers is 11 and 12.

Monday, October 15

Quantitative Reasoning Math

Introduction to quantitative reasoning math

Quantitative reasoning is one of  the most useful application in mathematics concepts and skills.It is used to solve the  real-world problems. The students must solve this quantitative reasoning for improve their skills. It is very useful to solve the real life problems also.Here some of the quantitative reasoning problems has been solved. The practice problems are very useful to the students to improve their knowledge in the quantitative reasoning mathematics.

Number Theory Problems in Quantitative Reasoning Math

Find the largest number which perfectly divide 10110-1

Solution:

Given number is 10110-1

The simple way to solve the math problem is given below

1012 = 10201.
1012 - 1 = 10200. This is divisible by 100.

Similarly   for 1013 - 1 = 1030301 - 1 = 1030300.

So you can conclude that (1011 - 1) to (1019 - 1) will be divisible by 100.

(10110 - 1) to (10199 - 1) will be divisible by 1000.

Therefore, (10110 - 1) will be divisible by the large number 10^10

2.Find the minimum value of tiles required in a top floor of breadth 3 meters 78 cm and height 1 meters 74 cm?

Solution for math:

The tiles used in top floor are square. Therefore, the breadth of the tile = height of the tile. As we have to usewhole number of tiles, the side of the tiles should a factor of both 3 m 78 cm and 1m 74. And it should be the highest factor of 3m 78 cm and 1m 74.

3 m 78 cm = 378 cm and 1 m 74 cm = 174 cm.

The HCF of 378 and 174 = 6

Hence, the side of the square is 6.

The number of such tiles required =` (378xx174)/(6xx6)`

The total tiles required = 1827 marbles.

Percentage Problems in Quantitative Reasoning Math

If the price of book increases by 10% and Raj intends to spend only an additional 5% on book, by how much % will he reduce the quantity of book purchased?

Solution for math:

Let the price of 1 book be Rs.x and let Raj initially buy 'y' books.

Therefore, he would have spent Rs. xy on book

When the price of book increases by 10%, the new price per l book is 1.10x.


Raj intends to increase the amount he spends on book by 5%.

i.e., he is willing to spend xy + 5% of xy = 1.05xy


Let the new quantity of book that he can get be 'q'.

Then, `1.10x * q = 1.05xy`
Or `q = (1.05xy)/(1.10x)=(1.05)/(1.10)` y= 0.95y.


As the new quantity that he can buy is 0.95y, he gets 0.05y lesser than what he used to get earlier.

Or a reduction of 5%.

2. A student  who gets 10% marks fails by 5 marks but another student who gets 21% marks gets 6% more than the passing marks. Find the maximum marks.

Solution for math

From the given data pass percentage is 21% - 6% = 15%

By hypothesis, 15% of x – 10% of x = 5 (marks)

i.e., 5% of x = 5

Therefore, x = 100 marks.