Online Solve Mathematics

Introduction to online solve mathematics:

Mathematics is the study of the dimension, properties, and interaction of quantities and sets, using symbols and numbers. Mathematics is used in our daily life. Mathematics includes algebra, geometry, calculus, etc. Step by step explanation is very useful to understand the concepts of math. Through the online, student can gain more knowledge even by staying in their home itself. Now, we are going to see some of the problems to solve mathematics online.

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Problems to solve mathematics online:


Example problem 1:

Simplify the expression: 15x + 8y - 2 + 7x + 12y + 17

Solution:

This expression can be simplified by combining like terms

+15 x and +7x are like terms, and can be combined to give +22x,

+8y and +12y combine to give +20y, and

-2 and +17 combine to give +15.

So after simplifying, this expression becomes: 22x + 20y + 15.

Example problem 2:

Subtracting fractions: `3/4 - 1/5`

Solution:

The common denominator of 4 and 5 is 20.

In this example, we need to multiply the fraction  `3 / 4`  by 5 and multiply `1 / 5` by 4. So, Equivalent fraction of `3 / 4` is `15 / 20` and the equivalent fraction of `1 / 5` is` 4 / 20` .

`3 / 4 - 1 / 5 = 15 / 20 - 4 / 20`

Now, the denominators are same, so we have to subtract the numerators.

`3 / 4 - 1 / 5 = (15 - 4) / 20`

=`11 / 20`

So, the answer is `11 / 20.`


Few more problems to solve mathematics online:


Example problem 3:

Solve the inequality s: 17.5s – 33 < 37

Solution:

17.5s – 33 < 37

Add 33 on both side of the inequality

17.5s – 33 + 33 < 37 + 33

17.5s < 70

Divide by 17.5 on both side of the inequality

`(17.5s) / 17.5 < 70 / 17.5`

s < 4

So, the solution is (-infinity, 4).

Example problem 4:

The base of a cylinder has the radius of 4.5 cm and the height is 8 cm. Determine the lateral surface area of the solid cylinder.

Solution:

Radius = 4.5cm

Height = 8cm

Formula for lateral surface area = 2* `pi` * r * h.

Here given that, r = 4.5cm and h = 8cm.

Lateral surface area of the cylinder = 2 * 3.14 * 4.5 * 8

= 226.29 cm^2.

So, the lateral surface area of cylinder is 226.29 cm^2.


Practice problems to solve mathematics online:


1)    Subtracting fractions: `3 / 5 - 1 / 4` . (Answer: `7 / 20` ).

2)    Solve the inequality: 13.4s – 2.6 > 51. (Answer: s > 4).

3)    The base of a cylinder has the radius of 3.8 cm and the height is 7 cm. Determine the lateral surface area of the solid cylinder. (Answer: 167.05 cm^2).

Solving Learning Mathematics

Introduction to solving learning mathematics:

Mathematics is related to the properties, dimension, and interaction of quantities and sets, using numbers and symbols. Mathematics is used in our daily life. Mathematics includes various topics such as algebra, geometry, trigonometric, calculus, etc. Step by step clear explanation is more helpful to understand the basic concepts involved in math. Now, we are going to see some of mathematics problems learning.

Solving learning mathematics problems:


Example problem 1:

Solve for the variable r:  3r – 13 = 47 - 2r

Solution:

3r – 13 = 47 - 2r

Add 13 on both sides of the equation

3r – 13 + 13 = 47 - 2r + 13

3r = -2r + 60

Add 2r on both sides of the equation

3r+ 2r = -2r + 60 + 2r

5r = 60

Divide by 5 on both sides of the equation

`(5r) / 5 = 60 / 5`

By solving this, we get

r = 12

So, the answer is r = 12.

Example problem 2:

Marked price of a furniture is `$` 450. It is sold at a discount of 20%. Find the discount and its selling price.

Solution:

Marked price of the furniture = `$` 450

Rate of discount = 20%

Discount allowed = 20% of `$` 450=`20 / 100` × `$` 450 = `$` 90

Therefore, Selling price of the furniture = `$` 450 – `$` 90 = `$` 360.


Few more solving learning mathematics problems:


Example problem 3:

Find the Mean value for the given set of numbers: 42, 48, 43, 45.

Solution:

Mean = Sum of the values
Total number of values.

Mean   =`(42 + 48 + 43 + 45) / 4`

=`178 / 4`

= 44.5

So, the mean value is 44.5.

Example problem 4:

Find x and y intercept for the equation of line 13x +6.5y = 26.

Solution:-

Given equation is 13x + 6.5y = 26.

x intercept means plug y = 0 in the given equation

13x + 6.5(0) = 26

13x = 26

By Solving this, we get

x = 2

y intercept means plug x = 0 in the given equation

13(0) + 6.5y = 26

6.5y = 26

y =4

So, the x intercept is (2, 0) and the y intercept is (0, 4).

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Practice problems for mathematics learning:
1) Find the value of p: 7p +17 = 66.

(Answer: p = 7).

2)  Find x intercept for the equation of line 4x + 6y = 30.

[Answer: (7.5, 0)].

3) Find the mean value for the given set of numbers: 10, 20, 30, 40.

(Answer: 25).

Solving Ks-3 Mathematics Tuitions

Introduction to solving ks-3 mathematics tuitions:

Mathematics is one of the basic knowledge to be known. Ks-3 means key stage 3 which refers to the three year schooling for students who are in the age of 11-14. These types of systems are followed in England and Northern Ireland. The ks-3 term of study is generally expressed as year 7, year 8 and year 9 studies. In online, many websites provides free help on ks-3 maths problem. In online, students can get help with all subject problems. In this article, we are going to see about, ks-3 mathematics problem solving online.


Practice problems on solving ks-3 mathematics tuitions:


Solving Ks-3 mathematics:


Ex 1: Find the place value of the number 9 in the given number 319
Sol :  The place value of 9 in the given number is, 1’s place
Hence the answer is 1’s place.
Ex 2:  Write the expanded form of 8290.
Sol :  The number 8290 can be written in expanded form as,
8290 = 8000 + 200 + 90
The answer is 8000 + 200 + 90.
Ex 3:  Express 16/32 as a percentage.
Sol :  16/32 = 16/32*100
On solving this we get,
= 0.5*100
= 50%
The solution is 50%
Ex 4:   In a school, there are total of 462 students. In that school there are 11 classrooms, find the number of students for each class.
Sol :  Total number of students = 462
Number of classrooms = 11
Number of students per class = x
Number of students per class = Total number of students/ number of classrooms
On solving this we get,
= 462/11
= 42
The answer is 42.

Ex 5:  Find the value of 5x, when x is 12
Sol :  Given: x = 12
5x = 5*12
= 60
Then answer is 60.
Ex 6:  Find the value of 4x2 + 3, when x is 4.
Sol :  Given: x = 4
4x2 + 3 = 4(4)2 + 3
= 4(16) + 3
= 64 + 3
= 67
The answer is 67.


Practice problems solving ks-3 mathematics tutions:


Problem 1: Find the place of 8 in the given number, 3859
Solution: 100’s place
Problem 2: Express 32/45 as a percentage
Solution: 71.11%
Problem 3: Find x, 22x, where x = 5
Solution: 110
Problem 4: Express 178 cents in dollars
Solution: 1.78 dollars

Prepare for Mathematics Problems

Introduction to prepare for mathematics problems:

Mathematics is the study of the dimension, properties, and interaction of quantities and sets, using symbols and numbers. Mathematics is used in our daily life. Mathematics includes algebra, geometry, calculus, etc. Step by step explanation is very useful to understand the concepts of math. Now, we are going to prepare for mathematics problems.

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Problems to prepare mathematics:


Example problem 1:

Solve an equation for the variable r:` (r / 4)` - 28 = -33

Solution:

`(r / 4) ` - 28 = -33

Add 28 on both sides of the equation

`(r / 4) ` – 28 + 28 = - 33 + 28

`(r / 4) ` = -5

Multiply 4 on both sides of the equation

`(r / 4)` * 4 = -5 * 4

r = -20

So, r = -20 is the solution of the given equation.

Example problem 2:

Solve the inequality: 2r – 83 < -61

Solution:

2r – 83 < -61

Add 83 on both side of the inequality

2t – 83 + 83 < -61 + 83

2r < 22

Divide by 2 on both side of the inequality

`(2r) / 2 < 22 / 2`

r < 11

So, the solution is (-infinity, 11).


Few more problems to prepare mathematics:


Example problem 3:

Find the x and y intercept of the equation: 7x + 3.5y = 14.

Solution:

7x + 3.5y = 14

To find the x intercept value, plug y = 0 in the given equation

7x + 3.5(0) = 14

7x = 14

x = 2

So, the x intercept is (2, 0).

To find the y intercept value, plug x = 0 in the given equation

7(0) + 3.5y = 14

3.5y = 14

y = 4

So, the y intercept is (0, 4).

Example problem 4:

Find the area of trapezoid whose parallel sides are 10cm and 7cm and height is 8cm.

Solution:

Base 1 = 10cm

Base 2 = 7cm

Height = 8cm

Area of trapezoid = `(1 / 2)` h(a + b)

= `(1/2)` (8) (10 + 7)

= 68cm^2.

So, the area of trapezoid is 68cm^2.

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Practice problems to prepare mathematics:


1)      Solve for the variable d:  10d + 4 = 18 + 3d (Answer: d = 2).

2)      Solve for the variable r:  18r + 1 = 37 (Answer: r = 2).

3)      Find the area of trapezoid whose parallel sides are 9cm and 6cm and height is 5cm. (Answer: 37.5cm^2).

Basic Mathematics for College Students

Introduction to basic mathematics for college students:

There are certain math topics are appeared in college which we already read in school period.Those topics are very basics for college students.The following mathematics topics are basics for college students. They are, algebra problems, geometry measures, probability problems and linear equations. By referring those topics, the college students recall the concepts of the topics , so that they can do themselves. Let we see some basic problems to basic mathematics for college students.


Example problems to basic mathematics for college students:


The following problems are examples for basic mathematics for college students.

Basic mathematics - problem1) Solve the linear equation, 3a+6b-14 = 16, a+3b- 6 = 12.

Solution:

Here we need to find the value of a and b,

The given equations are 3a+6b-14 =16 and a - 6b-6 =12

3a+6b-14 = 16

a  - 6b - 6  = 12.

We can write the above equation as

3a + 6b = 16+14

a - 6b  = 12+6

From the above equation, we get

3a + 6b = 30------------------------->1

a  - 6b  = 18------------------------->2

4a        = 48

4a = 48

Divide by 4 on both sides, we get

`(4a)/4` = `(48)/4`

a  = 12.

Apply the 'a' value in equation (1),we get

3a+6b= 30

3(12)+6b  = 30

36 + 6b    = 30.

Add -36 on both sides, we get

36-36 +6b = 30-36

6b = -6

Divide by 6 on both sides, we get

`(6b)/ 6` = -`6/ 6`

b  = -1.

The values of a and b are , 12 and -1.

Problem2) Find the value of  D , 2d+5e+6f = 80-4d+20, where e=2 and f=3

Solution:

Here we have the value of e and f as  2 and 3.

Apply the values in the given equation,we get

2d +5e+6f = 80-4d+20

2d + 5 ( 2) +6(3) = 80-4d+20

2d +10 +18       = 80-4d+20

2d +28            = 80+20-4a

2d +4d         = 100 - 28

6d    = 72

Divide by 6 on both sides, we get

6d /6  = 72 /6

d    = 12

The value of d =12.

Problem3) Solve the following linear equation, 3p+3q = 18, 2p+3q = 14

Solution:

Here we need to find the value for P and Q.

The given equations are

3p + 3q   =  18 -------->1

2p + 3q   =   14---------->2

By changing the sign of the second equation values, we can solve the above problem.

3p + 3q  =18

-2p - 3q  =14

p = 4

Apply the p value in equation (1) , we get

3 (4) + 3q  = 18

12 + 3q   = 18

Add -12 on both sides, we get

12-12 +3q = 18-12

3q = 6

Divide by 3 on both sides, we get

3q/3 = 6/3

q = 2

The values of m and q are , 4 and 2.

Problem 4:  If S and T values are 2 in the given equation , 10S +8T +6U = 78, find the value of U?

Solution:

Given equation          = 10S + 8T + 6U = 78

Known values  are , S = T =  2

Apply S and T values in the above equation,we get

10S + 8T + 6U      = 78.

10(2) + 8(2) + 6U  = 78.

20 + 16 + 6U     = 78

36 + 6U     = 78

Add -36 on both sides, we get

36 - 36 + 6U = 78 - 36

6U    =  42

Divide by 6 on both sides, we get

6U/6  = 42/6

U = 7

The value of U= 7.

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Practice problems to basic mathematics for college students:


Try to solve the following mathematics problems.

Problem1) 2a+2b+4c = 10, a+3b+c = 22, 2a+3b+2c=14

Answer: a=-11,b=10,c=3.

Problem2) 4x + 6y = 28, 2x+4y=18

Answer : x = 1,y=4

ABC of Mathematics

Introduction to ABC of maths:

Mathematics plays a very important role in humans life. Mathematical thinking is very important for everyone. In every work of a human we need mathematics.


Humans use the mathematics in doing any work. For example consider:
Arithmetic:  in counting and sorting,
Geometry: in spacing and distancing,
Statics: in balancing and weighting,
Probability: in guessing and judging


ABC OF MATHS means the fundamentals and basics of mathematics.

Brief explanation of ABC of maths:


NUMBER:
Number in mathematics is just a word or a symbol which is used for counting and also to say where something comes in a series.
Generally numbers are used for counting and calculating.


There are different kinds of numbers which includes: natural numbers, integers or whole numbers, cardinal numbers, ordinal numbers, rational numbers, real numbers, complex numbers etc.

NATURAL NUMBERS:
Natural numbers start from the 1, 2………infinity. They form the endless chain.

INTEGERS:
Integers also form the endless chain and it includes negatives and zero also.
…….……..-3, -2, -1, 0, 1, 2, 3……………..

Integers are also known as whole numbers.


CARDINAL NUMBERS:
Cardinal number shows how many there are. They are used for counting.


ORDINAL NUMBERS:
Ordinal numbers tells about the order of the object being counted. Places in a sequence are shown by ordinal numbers.


RATIONAL NUMBERS:
Rational numbers are the numbers which does not includes like an square root of 2. It includes the integers and fractions.


REAL NUMBERS:
Real numbers are the numbers which also includes the numbers like square root of 2.


COMPLEX NUMBERS:
Complex numbers includes the imaginary numbers also like square root of -1.


There are also some special numbers included in ABC of mathematics. They include zero and Arabic number system. Zero is the number which was discovered by Indian and it is a great discovery without zero there is no value or reason of mathematics.
There are different kinds of scales which are used to classify and quantify and also to measure things. The different types of scales includes Binary scale, Nominal scale, Ordinal scale, Interval scale, Ratio scale
We also use roman numbers. FORMULA in mathematics is nothing but a rule.

Everyday Mathematics 5th Grade

Introduction to everyday mathematics 5th grade:

For 5th grade students mathematics is divided into different categories. In grade 5 students can learn Simplification using BODMAS, word problems, unitary methods, Multiples and factors, HCF and LCM, Multiplication and Division of fractional numbers and decimals. They also learn about money, percentage, profit and loss, Simple interest etc.They learn measurement of length, mass and capacity. In geometry they can learn about the types of angles, triangles, element of circle, relation between diameter and radius etc.


everyday mathematics 5th grade - Some Examples


In 5th grade we can learn everyday common mathematics as follows:

(1) Unitary Method: The simple rule of unitary method that if we are given the cost of one object, we can find the cost of many objects by multiplying the cost of one object with the number of objects and if we are given the cost of several objects, we an find the cost of one object by dividing the cost of several objects by the number of objects.

Example:  The weight of 25 bags of rice is 650 kg. Find the weight of hundred bags of rice?

Solution: since the weight of 25 bags of rice is 650kg.

Then the weight of 1 bag of rice is 650 ÷ 25

26kg

Then weight of 100 bags of rice is 26 x 100

2600 kg

Answer: weight of 100 bags of rice is 2600 kg.

(2) HCF and LCM:  We define the HCF as the highest common factor.HCF of two given numbers is the highest number that divides the given numbers exactly without leaving any remainder.

Example: Find HCF of 136, 170 and 255 by division method:

Solutions: First we find the HCF of 136 and 170

136)170(1

136

34

HCF of 136 and 170 = 34

Now we find the HCF of 34 and 255

34)255(7

238

17)34(2

34

0

HCF of 34 and 255 =17

Hence HCF of 136,170 and 255 = 17

LCM: The lowest common multiple of two or more numbers is the smallest number which is a multiple of each of the numbers.

Example: Find the LCM of 20, 30 and 50 by division method:

2] 20, 30, 50

5] 10, 15, 25

2,   3,   5

LCM = 2x 5x 2x 3x 5 = 300


everyday mathematics 5th grade - more Examples


Decimal numbers: Conversion of a decimal fraction into fraction number:

Write the given number without a decimal point in the numerator.
Write 1 in the denominator followed by as many zeros as the decimal places.
Then write the resulting fraction in the lowest form.
Example:

(a)    1.5 = 15 / 10 =3 /2

(b)   54.972 = 54972 /1000

= 13743 / 250

Find the sum:

(a)    205.40, 80.75 and 1493.50

All decimal points should be in a column in the question and answer:

2 0 5.  40

80.  75

14 93 .50

1 7 7 9.65

Percent: Percent means for every hundred. To convert a % into fraction, place the given number over 100 and reduce it to its lowest term.

Example: 20% = 20 / 100

=  1/5

150% = 150/100

=3/2

To find the percent of a given number:

Example: (a)   Find 50% of 75

50/100 x 75

= 75/2 = 37 ½ Ans.

(b)   What % is 25 of 200

25/200 x 100

=    12 ½ Ans.