Basic Mathematics for College Students

Introduction to basic mathematics for college students:

There are certain math topics are appeared in college which we already read in school period.Those topics are very basics for college students.The following mathematics topics are basics for college students. They are, algebra problems, geometry measures, probability problems and linear equations. By referring those topics, the college students recall the concepts of the topics , so that they can do themselves. Let we see some basic problems to basic mathematics for college students.


Example problems to basic mathematics for college students:


The following problems are examples for basic mathematics for college students.

Basic mathematics - problem1) Solve the linear equation, 3a+6b-14 = 16, a+3b- 6 = 12.

Solution:

Here we need to find the value of a and b,

The given equations are 3a+6b-14 =16 and a - 6b-6 =12

3a+6b-14 = 16

a  - 6b - 6  = 12.

We can write the above equation as

3a + 6b = 16+14

a - 6b  = 12+6

From the above equation, we get

3a + 6b = 30------------------------->1

a  - 6b  = 18------------------------->2

4a        = 48

4a = 48

Divide by 4 on both sides, we get

`(4a)/4` = `(48)/4`

a  = 12.

Apply the 'a' value in equation (1),we get

3a+6b= 30

3(12)+6b  = 30

36 + 6b    = 30.

Add -36 on both sides, we get

36-36 +6b = 30-36

6b = -6

Divide by 6 on both sides, we get

`(6b)/ 6` = -`6/ 6`

b  = -1.

The values of a and b are , 12 and -1.

Problem2) Find the value of  D , 2d+5e+6f = 80-4d+20, where e=2 and f=3

Solution:

Here we have the value of e and f as  2 and 3.

Apply the values in the given equation,we get

2d +5e+6f = 80-4d+20

2d + 5 ( 2) +6(3) = 80-4d+20

2d +10 +18       = 80-4d+20

2d +28            = 80+20-4a

2d +4d         = 100 - 28

6d    = 72

Divide by 6 on both sides, we get

6d /6  = 72 /6

d    = 12

The value of d =12.

Problem3) Solve the following linear equation, 3p+3q = 18, 2p+3q = 14

Solution:

Here we need to find the value for P and Q.

The given equations are

3p + 3q   =  18 -------->1

2p + 3q   =   14---------->2

By changing the sign of the second equation values, we can solve the above problem.

3p + 3q  =18

-2p - 3q  =14

p = 4

Apply the p value in equation (1) , we get

3 (4) + 3q  = 18

12 + 3q   = 18

Add -12 on both sides, we get

12-12 +3q = 18-12

3q = 6

Divide by 3 on both sides, we get

3q/3 = 6/3

q = 2

The values of m and q are , 4 and 2.

Problem 4:  If S and T values are 2 in the given equation , 10S +8T +6U = 78, find the value of U?

Solution:

Given equation          = 10S + 8T + 6U = 78

Known values  are , S = T =  2

Apply S and T values in the above equation,we get

10S + 8T + 6U      = 78.

10(2) + 8(2) + 6U  = 78.

20 + 16 + 6U     = 78

36 + 6U     = 78

Add -36 on both sides, we get

36 - 36 + 6U = 78 - 36

6U    =  42

Divide by 6 on both sides, we get

6U/6  = 42/6

U = 7

The value of U= 7.

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Practice problems to basic mathematics for college students:


Try to solve the following mathematics problems.

Problem1) 2a+2b+4c = 10, a+3b+c = 22, 2a+3b+2c=14

Answer: a=-11,b=10,c=3.

Problem2) 4x + 6y = 28, 2x+4y=18

Answer : x = 1,y=4