Introduction of mathematics dealing with functions:
The mathematics dealing with functions in the form of f(x) = 2x+3, we are assigning the value for variable x in the given function so that we can solve the functions in math. Now we are given several values for variable x in the given function and finding the solution for each function. Example for s function is f(y)=19y+12,function f(2). Using the square equation solve a function rule of f(x) = 2x2 +4x +28, function of f(2).
Example of mathematics dealing with functions:
f(2) = 2x+2 and f(x) =` (x+2)/2` , here the variable of x is 2.
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Problems how to find mathematics dealing with functions in square equations
Problem 1 : Using square equation find the mathematics dealing with functions of f(9), when f(x) = `(x+2)/2` +2.
Solution : Here the variable is given as 9 find the function of f(9).
f(x) = `(x+2)/2` + 2 find the f(9)
The value of x is 9 is given
f(9) = ` (9+2)/2 ` + 2
f(9) = `11/2 ` + 2
f(9) = 5.5+2
f(9) = 7.5
Problem 2 : Using square equation find the mathematics dealing with functions of f(8), when f(x) = `(x+3)/4` +12.
Solution :
Here the variable is given as 8 find the function notation of f(8).
f(x) =`(x+3)/4 ` +12 find the f(8)
The value of x is 8 is given
f(8) = `(8+3)/4 ` +12
f(8) = `(11)/4` +12
f(8) = 2.75 + 12
f(8) = 14.75
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Problems in mathematics dealing with functions
Problems1: using mathematics dealing with functions of f(3), When f(x ) = `(2(x+3))/8`
Solution:
Using the function f(3) in the constant function
f(x) =` (2x+6)/8`
f(3) = `(2xx3+6)/8 ` here substitute x value 3 in the given constant function
f(3) = `12/8.`
f(3) = 1.5
Problems 2: using mathematics dealing with functions of f(4). When f(x ) = `(2(x+6))/4`
Solution:
Using function f(4) in the constant function
f(x) = `(2(x+6))/4`
f(4) = `(2(x+6))/4` here substitute x value 4 in the given constant function
f(4) =` (2xx4+12)/4.`
f(4) = `(8+12)/4`
f(4) = `20/4`
f(4) = 5
The mathematics dealing with functions in the form of f(x) = 2x+3, we are assigning the value for variable x in the given function so that we can solve the functions in math. Now we are given several values for variable x in the given function and finding the solution for each function. Example for s function is f(y)=19y+12,function f(2). Using the square equation solve a function rule of f(x) = 2x2 +4x +28, function of f(2).
Example of mathematics dealing with functions:
f(2) = 2x+2 and f(x) =` (x+2)/2` , here the variable of x is 2.
Please express your views of this topic Exponential Function Rules by commenting on blog.
Problems how to find mathematics dealing with functions in square equations
Problem 1 : Using square equation find the mathematics dealing with functions of f(9), when f(x) = `(x+2)/2` +2.
Solution : Here the variable is given as 9 find the function of f(9).
f(x) = `(x+2)/2` + 2 find the f(9)
The value of x is 9 is given
f(9) = ` (9+2)/2 ` + 2
f(9) = `11/2 ` + 2
f(9) = 5.5+2
f(9) = 7.5
Problem 2 : Using square equation find the mathematics dealing with functions of f(8), when f(x) = `(x+3)/4` +12.
Solution :
Here the variable is given as 8 find the function notation of f(8).
f(x) =`(x+3)/4 ` +12 find the f(8)
The value of x is 8 is given
f(8) = `(8+3)/4 ` +12
f(8) = `(11)/4` +12
f(8) = 2.75 + 12
f(8) = 14.75
I have recently faced lot of problem while learning Limit Function, But thank to online resources of math which helped me to learn myself easily on net.
Problems in mathematics dealing with functions
Problems1: using mathematics dealing with functions of f(3), When f(x ) = `(2(x+3))/8`
Solution:
Using the function f(3) in the constant function
f(x) =` (2x+6)/8`
f(3) = `(2xx3+6)/8 ` here substitute x value 3 in the given constant function
f(3) = `12/8.`
f(3) = 1.5
Problems 2: using mathematics dealing with functions of f(4). When f(x ) = `(2(x+6))/4`
Solution:
Using function f(4) in the constant function
f(x) = `(2(x+6))/4`
f(4) = `(2(x+6))/4` here substitute x value 4 in the given constant function
f(4) =` (2xx4+12)/4.`
f(4) = `(8+12)/4`
f(4) = `20/4`
f(4) = 5
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